+0  
 
0
292
2
avatar+206 

Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph in the same direction as car A. At what time will car B pass car A?
 

LunarRoxey  Apr 4, 2017
 #1
avatar+89702 
+2

We can use logic here :

 

Note that when Car B started......Car A has already traveled 30 miles.......so.....Car B must make up a 30 mile gap

 

And the difference in speeds  is  40 - 30  = 10 mph

 

So.....Car B  makes up a 10 mile gap every hour.....so.....it must take Car B  3 hours to catch Car A, i.e, at  1 PM

 

 

cool cool cool

CPhill  Apr 4, 2017
 #2
avatar
+1

Let time = t,  Speed = Distance/Time. Then we have:

30(t+1) =40t, solve for t

t =3 hours - or about 1:00 pm, when car B catches up with car A.

Guest Apr 4, 2017

8 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.