Approximately 9% of men have a type of color blindness that prevents them from distinguishing between red and green. If two men are selected at random from a large group of men, find the probability that both will have this type of color blindness.
The probability will be .09 x .09 = .0081 = .81 %
really? its not that tricky? hahaha thanks ! i'm thinking too much i guess thanks :)
Yep it really is that simple :))