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# area of a sector

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a circle has a sector with the area 9pi and central angle of 17/9pi radians

Mar 15, 2019

#1
+234
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So what are we solving for here? I'm assuming that the circle has the area of $$9\pi$$ . If so, then we should convert radians to degrees, which gives us 340 degrees. So a 20 degree sector. I think that the sector that you're talking about is the one with 340 degrees. To find the ratio of the sector to circle, we get $$\frac {340}{360} = \frac {17}{18}$$.So the sector has area $$\frac {17\cdot 9\pi}{18} = \frac {153\pi}{18}$$.

Hope this helps!

Mar 15, 2019
#2
+101729
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What is the question?

Mar 15, 2019