We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
98
2
avatar

a circle has a sector with the area 9pi and central angle of 17/9pi radians

 Mar 15, 2019
 #1
avatar+234 
+1

So what are we solving for here? I'm assuming that the circle has the area of \(9\pi\) . If so, then we should convert radians to degrees, which gives us 340 degrees. So a 20 degree sector. I think that the sector that you're talking about is the one with 340 degrees. To find the ratio of the sector to circle, we get \(\frac {340}{360} = \frac {17}{18}\).So the sector has area \(\frac {17\cdot 9\pi}{18} = \frac {153\pi}{18}\).

 

Hope this helps!

 Mar 15, 2019
 #2
avatar+102763 
0

What is the question?      

 Mar 15, 2019

18 Online Users