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a circle has a sector with the area 9pi and central angle of 17/9pi radians

 Mar 15, 2019
 #1
avatar+235 
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So what are we solving for here? I'm assuming that the circle has the area of \(9\pi\) . If so, then we should convert radians to degrees, which gives us 340 degrees. So a 20 degree sector. I think that the sector that you're talking about is the one with 340 degrees. To find the ratio of the sector to circle, we get \(\frac {340}{360} = \frac {17}{18}\).So the sector has area \(\frac {17\cdot 9\pi}{18} = \frac {153\pi}{18}\).

 

Hope this helps!

 Mar 15, 2019
 #2
avatar+110149 
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What is the question?      

 Mar 15, 2019

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