Area of hexagon

Hi Chris and Bertie,

That is only true if it is a regular hexagon.

Is that just a statement, or is it meant to be a question ?

A question

What I would do is divide it into triangles and find the area of those. If it's not to scale or somthing, find the formula online.

I hope this helped. 

In that case it's equal to the sum of the areas of six equilateral triangles.

You don't need to find the forumula online.

Area of a triangle is 1/2 * base * perpendicular height

It depends what lengths or angles you are given as to how you go about doing this.

Are you talking about a regular hexagon? What info do you have?

Re: Area of hexagon

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Let's think about this for just a second. A hexagon is just composed of 6 equilateral triangles. Then the area of one of these triangles is just (1/2)s²sin(60°) = (1/2)s²(√(3)/2) = (1/4)s²(√(3), where s is the side length of the hexagon. And since we have 6 of these triangles, then the total area is just 6* (1/4)s²(√(3)=

(3√(3))/2*s²