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# Area of hexagon

#7
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Hi Chris and Bertie,

That is only true if it is a regular hexagon.

Apr 24, 2014

#1
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Is that just a statement, or is it meant to be a question ?

Apr 23, 2014
#3
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What I would do is divide it into triangles and find the area of those. If it's not to scale or somthing, find the formula online.

I hope this helped.

Apr 23, 2014
#4
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In that case it's equal to the sum of the areas of six equilateral triangles.

Apr 23, 2014
#5
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You don't need to find the forumula online.

Area of a triangle is 1/2 * base * perpendicular height

It depends what lengths or angles you are given as to how you go about doing this.

Are you talking about a regular hexagon? What info do you have?

Apr 24, 2014
#6
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Re: Area of hexagon

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Let's think about this for just a second. A hexagon is just composed of 6 equilateral triangles. Then the area of one of these triangles is just (1/2)s2sin(60°) = (1/2)s2(√(3)/2) = (1/4)s2(√(3), where s is the side length of the hexagon. And since we have 6 of these triangles, then the total area is just 6* (1/4)s2(√(3)=

(3√(3))/2*s2   Apr 24, 2014
#7
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