Square A has side lengths each measuring $x$ inches. Square B has side lengths each measuring $4x$ inches. What is the ratio of the area of the smaller square to the area of the larger square? Express your answer as a common fraction.
Square A area: x*x=x^2
Square B area: 4x*4x=16x^2
x/16x^2=1/16- is the ratio between square A and square B.