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a Family leaves their House on Monday at 8:15 am for a 1530 mile trip if the avreage speed 42.5 on what day and at what time do they arive?
 Mar 13, 2014
 #1
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Guest:

8-) a Family leaves their House on Monday at 8:15 am for a 1530 mile trip if the avreage speed 42.5 on what day and at what time do they arive?



Speed: 42.5 mph
Distance: 1530 miles
time: x

Time = distance / speed

Time = ____

You'll have your time in hour, so at this point you should be able to calculate the day and the time.
 Mar 13, 2014
 #2
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Guest:

8-) a Family leaves their House on Monday at 8:15 am for a 1530 mile trip if the avreage speed 42.5 on what day and at what time do they arive?



Sam is right. I just want to look at it a little more.

You haven't given units for the speed. I will assume it is 42.5 miles per hour but it should have been in the question.

Now if it is 42.5miles/1 hour. I can flip that uupside down and say it is 1hour/42.5 miles

I can do that because if i go 42.5miles in 1 hour then I can say that in 1 hour I will go 42.5miles.
Now
1 hour/42.5miles * 1530 miles = (1*1530hours) / 42.5 [ the miles cancel out - and yes you can do that too]

= 1530/42.5 hours = 36 hours = exactly 1 and a half days

Leave Monday 8:15am ==> arrive Tues 8:15pm

My method for doing rates is unusual but I don't know why because it is by far the best method that there is. (I wish there was a nodding emicon that I could insert. )
 Mar 14, 2014

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