+148 Ari and Matthew are both running toward the soccer ball during a game.
Ari's path is represented by the parametric equations x(t)=36+1/6t,y(t)=24+1/8t, where t is on the interval [0,50] and t is measured in tenths of seconds.
Matthew's path is represented by the parametric equations x(t)=32+1/4t, y(t)=18+1/4t, where t is on the interval [0,50] and t is measured in tenths of seconds.
Do the boys collide? If so, when do they collide?
Ari and Matthew collide at 3.2 seconds.
Ari and Matthew collide at 4.8 seconds.
Ari and Matthew collide at 2.4 seconds.
Ari and Matthew do not collide.
+280 The interval [0,50] would mean that we use numbers (t) between 0 and 50 to replace with x and y. This would be rather difficult to solve since it would involve a lot of work.
So, to make this easier, I used the numbers given in the multiple choices, 3.2, 4.8, and 2.4. Because t is measured in tenths of seconds, you'd multiply the numbers by ten, making the numbers 32, 48, and 24. (This will make more sense at the end.)
Using these numbers, make a chart representing Ari's and Matthew's path.
Ari's Path
| t | x(t) = 36 + (1/6) t | y(t) = 24 + (1/8) t |
|---|---|---|
| 24 | 36 + (1/6) t = 36 + (1/6) (24) = 40 | 24 + (1/8) t = 24 + (1/8) (24) = 27 |
| 32 | 36 + (1/6) t = 36 + (1/6) (32) = 41.3333... | 24 + (1/8) t = 24 + (1/8) (32) = 28 |
| 48 | 36 + (1/6) t = 36 + (1/6) (48) = 44 | 24 + (1/8) t = 24 + (1/8) (48) = 30 |
Matthew's Path
| t | x(t) = 32 + (1/4) t | y(t) = 18 + (1/4) t |
|---|---|---|
| 24 | 32 + (1/4) t = 32 + (1/4) (24) = 38 | 18 + (1/4) t = 18 + (1/4) (24) = 24 |
| 32 | 32 + (1/4) t = 32 + (1/4) (32) = 40 | 18 + (1/4) t = 18 + (1/4) (32) = 26 |
| 48 | 32 + (1/4) t = 32 + (1/4) (48) = 44 | 18 + (1/4) t = 18 + (1/4) (48) = 30 |
Next, you would identify if Ari and Matthew collide by looking at the end results of the x and y. If NONE of the results match, then do NOT collide. If they do collide, you can determine the answer by simply dividing (t) by ten to get your final answer. (t) is the number in red.
The end results show that Ari and Mattew do collide at (44, 30). (t) is 48.
Because t is measured in tenths of seconds, you would divide 48 by 10.
48 / 10 = 4.8
Your answer for when they would collide would then be 4.8.
Ari and Matthew collide at 4.8 seconds.
