+0  
 
0
281
6
avatar+315 

Pre-calculus/trig

 Apr 16, 2019
 #1
avatar+110780 
+1

Hi Cupcake,

 

To answer this question you just need to recognise that 

 

\(n(cos\theta+isin\theta)=ne^{\theta i}\)

 

Convert them both to this form,

do the division

 then convert the answer back to the original form.   laugh

 Apr 16, 2019
 #2
avatar+110780 
0

Do you understand cupcake?  Have you figured out the answer yet?

 Apr 16, 2019
 #3
avatar+315 
+1

I believe the answer is either B. or D. 

Cupcake  Apr 16, 2019
 #4
avatar+315 
0

which answer did you get, Melody?

Cupcake  Apr 16, 2019
 #5
avatar+110780 
+2

\(\frac{5e^{\frac{\pi}{2}i}}{2e^{\frac{5\pi}{6}i}}\\~\\ =\frac{5}{2}e^{ (\frac{\pi}{2}-\frac{5\pi}{6}) i }\\~\\ =\frac{5}{2}e^{ (\frac{-2\pi}{6}) i }\\~\\ =\frac{5}{2}e^{ (\frac{-\pi}{3}) i }\\~\\ =\frac{5}{2}(cos(\frac{-\pi}{3})+isin(\frac{-\pi}{3})) \)

.
 Apr 16, 2019
 #6
avatar+315 
+1

Thank you!! smiley

Cupcake  Apr 16, 2019

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