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Find three numbers in an arithmetic sequence, where the sum of the second and third is 12, and the product of the first and second is 5.

 Apr 24, 2022
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First term== sqrt(51) - 6

 

2nd term == 1/3 (6 + sqrt(51))

 

3rd term == 1/3 (30 - sqrt(51))

 

[sqrt(51) - 6] * [1/3 (6 + sqrt(51))==5,  and:

 

[1/3 (6 + sqrt(51))]  +  [ 1/3 (30 - sqrt(51))]==12

 Apr 24, 2022

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