+0  
 
0
34
2
avatar

The middle number of a finite sequence of consecutive integers is 2022. The sum of the numbers after 2022 is twice the sum of those before 2022. How many integers are in the sequence? Thanks for help.

 Jul 20, 2022
 #1
avatar
0

There are 10 terms in the sequence.

 Jul 20, 2022
 #2
avatar
0

(n + 2021)/2 (2021 - n + 1) = (2021 - n + 1) (2021 - n + 2),..............(1) solve for n
n==675


(m + 2023) / 2 * (m - 2023 +1)==2(m - 2023 +1)(m - 2023 +2),.......(2)  solve for m
m ==3369


m - n + 1 ==3369 - 675 + 1==2,695 - number of terms

 Jul 20, 2022

2 Online Users