The middle number of a finite sequence of consecutive integers is 2022. The sum of the numbers after 2022 is twice the sum of those before 2022. How many integers are in the sequence? Thanks for help.
There are 10 terms in the sequence.
(n + 2021)/2 (2021 - n + 1) = (2021 - n + 1) (2021 - n + 2),..............(1) solve for n n==675
(m + 2023) / 2 * (m - 2023 +1)==2(m - 2023 +1)(m - 2023 +2),.......(2) solve for m m ==3369
m - n + 1 ==3369 - 675 + 1==2,695 - number of terms
