+-1098 In an arithmetic sequence, the 23rd term is 4, and the 25th term is 5. What is the 48th term?
+22 common difference = d
first term = t
The common difference would just be (5-4)/2 because there is one term in between the 23rd and 25th term. That means that the common difference is 0.5. We can say that the 25th term is t+24(0.5) and the 48th term is t+47(0.5). That means that the difference of the two terms is t+47(0.5)-t-24(0.5)= 23(0.5)=11.5. Because this is the difference, that means that the 48th term - 5 = 11.5. That means that the 48th term = 16.5.
So the answer is 16.5:)
+22 common difference = d
first term = t
The common difference would just be (5-4)/2 because there is one term in between the 23rd and 25th term. That means that the common difference is 0.5. We can say that the 25th term is t+24(0.5) and the 48th term is t+47(0.5). That means that the difference of the two terms is t+47(0.5)-t-24(0.5)= 23(0.5)=11.5. Because this is the difference, that means that the 48th term - 5 = 11.5. That means that the 48th term = 16.5.
So the answer is 16.5:)
