Arithmetic Sequences

The 23rd term is equal to: $a_1\times r^{22}$

The 26th terms is equal to: $a_1\times r^{25}$

So then $r^3=$$12\over{16}$

r^3 = 3/4

r = $\sqrt[3]{3\over4}$

32nd term would be 23rd term times r^9

$(\sqrt[3]{3\over4})^9$=3^3/4^3 = 27/64

16$\times$27/64 = 27/4