+280 In a geometric sequence, the 23rd term is 16 and the 26th term is 12. What is the 32nd term?
+302 The 23rd term is equal to: \(a_1\times r^{22}\)
The 26th terms is equal to: \(a_1\times r^{25}\)
So then \(r^3= \)\(12\over{16}\)
r^3 = 3/4
r = \(\sqrt[3]{3\over4}\)
32nd term would be 23rd term times r^9
\((\sqrt[3]{3\over4})^9\)=3^3/4^3 = 27/64
16\(\times\)27/64 = 27/4
