The measures of the three angles of a triangle form an arithmetic sequence. What must be the measure, in degrees, of at least one of its angles?


Let the three angles be    a1,  a1 + d  and  a1 + 2d


So....we have that


a1  +  (a1 + d)  +  (a1 + 2d)  =  180°


3a1  + 3d  =  180°          divide through by 3


(a1  +  d)   =  60°


So......one of the angles must be 60°



cool cool cool

CPhill  Jan 10, 2018

Thank you so much!

AnonymousConfusedGuy  Jan 10, 2018

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