a22=−49anda25=−58finda1
\mathbf{ \mathrm{Explicit~ Formula:} & \quad a_n = a_1 + (n-1)\cdot d } \\\\ \small{\text{$ \begin{array}{lrcl} & a_{22} &=& a_1 + 21 \cdot d \\ & a_{25} &=& a_1 + 24 \cdot d \\ \\ \hline \\ & a_{22} - a_1 &=& 21 \cdot d \\ & a_{25} - a_1 &=& 24 \cdot d \\ \\ \hline \\ & \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{21} {24}\\ \\ & \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{7} {8}\\\\ & 8\cdot ( a_{22} - a_1 ) &=& 7\cdot ( a_{25} - a_1 )\\ & 8\cdot a_{22} - 8\cdot a_1 &=& 7\cdot a_{25} - 7\cdot a_1\\ & 8\cdot a_1 - 7\cdot a_1 &=& 8\cdot a_{22} - 7\cdot a_{25} \\ & \mathbf{a_1} &\mathbf{=}& \mathbf{8\cdot a_{22} - 7\cdot a_{25}} \\\\ & a_1 &=& 8\cdot (-49) - 7 \cdot (-58 ) \\ & a_1 &=& -392 + 406 \\ & \mathbf{a_1} &\mathbf{=}& \mathbf{14} \end{array} $}}
-58 - (-49) = -9 is the difference in these terms which seems to imply that -9/3 = -3 is the common difference between terms
So......
-58 = a1 + d(n - 1)
-58 = a1 - 3(25 - 1)
-58 = a1 - 72 add 72 to both sides
14 = a1
a22=−49anda25=−58finda1
\mathbf{ \mathrm{Explicit~ Formula:} & \quad a_n = a_1 + (n-1)\cdot d } \\\\ \small{\text{$ \begin{array}{lrcl} & a_{22} &=& a_1 + 21 \cdot d \\ & a_{25} &=& a_1 + 24 \cdot d \\ \\ \hline \\ & a_{22} - a_1 &=& 21 \cdot d \\ & a_{25} - a_1 &=& 24 \cdot d \\ \\ \hline \\ & \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{21} {24}\\ \\ & \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{7} {8}\\\\ & 8\cdot ( a_{22} - a_1 ) &=& 7\cdot ( a_{25} - a_1 )\\ & 8\cdot a_{22} - 8\cdot a_1 &=& 7\cdot a_{25} - 7\cdot a_1\\ & 8\cdot a_1 - 7\cdot a_1 &=& 8\cdot a_{22} - 7\cdot a_{25} \\ & \mathbf{a_1} &\mathbf{=}& \mathbf{8\cdot a_{22} - 7\cdot a_{25}} \\\\ & a_1 &=& 8\cdot (-49) - 7 \cdot (-58 ) \\ & a_1 &=& -392 + 406 \\ & \mathbf{a_1} &\mathbf{=}& \mathbf{14} \end{array} $}}