$$\small{\text{$
\mathbf{
a_{22} = -49 \quad \mathrm{and} \quad a_{25}= -58 \quad \mathrm{find} \quad a_1
}
$}}$$
$$\mathbf{
\mathrm{Explicit~ Formula:}
& \quad a_n = a_1 + (n-1)\cdot d
} \\\\
\small{\text{$
\begin{array}{lrcl}
& a_{22} &=& a_1 + 21 \cdot d \\
& a_{25} &=& a_1 + 24 \cdot d \\
\\
\hline
\\
& a_{22} - a_1 &=& 21 \cdot d \\
& a_{25} - a_1 &=& 24 \cdot d \\
\\
\hline
\\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{21} {24}\\ \\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{7} {8}\\\\
& 8\cdot ( a_{22} - a_1 ) &=& 7\cdot ( a_{25} - a_1 )\\
& 8\cdot a_{22} - 8\cdot a_1 &=& 7\cdot a_{25} - 7\cdot a_1\\
& 8\cdot a_1 - 7\cdot a_1 &=& 8\cdot a_{22} - 7\cdot a_{25} \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{8\cdot a_{22} - 7\cdot a_{25}} \\\\
& a_1 &=& 8\cdot (-49) - 7 \cdot (-58 ) \\
& a_1 &=& -392 + 406 \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{14}
\end{array}
$}}$$
.
-58 - (-49) = -9 is the difference in these terms which seems to imply that -9/3 = -3 is the common difference between terms
So......
-58 = a1 + d(n - 1)
-58 = a1 - 3(25 - 1)
-58 = a1 - 72 add 72 to both sides
14 = a1
$$\small{\text{$
\mathbf{
a_{22} = -49 \quad \mathrm{and} \quad a_{25}= -58 \quad \mathrm{find} \quad a_1
}
$}}$$
$$\mathbf{
\mathrm{Explicit~ Formula:}
& \quad a_n = a_1 + (n-1)\cdot d
} \\\\
\small{\text{$
\begin{array}{lrcl}
& a_{22} &=& a_1 + 21 \cdot d \\
& a_{25} &=& a_1 + 24 \cdot d \\
\\
\hline
\\
& a_{22} - a_1 &=& 21 \cdot d \\
& a_{25} - a_1 &=& 24 \cdot d \\
\\
\hline
\\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{21} {24}\\ \\
& \dfrac{ a_{22} - a_1 } { a_{25} - a_1 } &=& \dfrac{7} {8}\\\\
& 8\cdot ( a_{22} - a_1 ) &=& 7\cdot ( a_{25} - a_1 )\\
& 8\cdot a_{22} - 8\cdot a_1 &=& 7\cdot a_{25} - 7\cdot a_1\\
& 8\cdot a_1 - 7\cdot a_1 &=& 8\cdot a_{22} - 7\cdot a_{25} \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{8\cdot a_{22} - 7\cdot a_{25}} \\\\
& a_1 &=& 8\cdot (-49) - 7 \cdot (-58 ) \\
& a_1 &=& -392 + 406 \\
& \mathbf{a_1} &\mathbf{=}& \mathbf{14}
\end{array}
$}}$$