In this particular arithmetic sequence, a8 = 28 and a16 = 108. What is the value of a24?
a24 = 188
a24 = 162
a24 = 198
a24 = 224
I know it's not B
The general formula is: an = a1 + (n - 1)d
a8 = 28 ---> a8 = a1 + (8 - 1)d ---> 28 = a1 + 7d
a16 = 108 ---> a16 = a1 + (16 - 1)d ---> 108 = a1 + 15d
Subtract down the columns: -80 = - 8d
---> d = 10
Substituting this value for d into the first equation: 28 = a1 + 7d
---> 28 = a1 + 7(10)
---> 28 = a1 + 70
---> a1 = -42
So the equation is: an = -42 + (n - 1)(10)
To find a24, substitue 24 in for n and solve.