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Assume that 10% of the population are le ft-handers. Wha t is the probability that in a class of 40 there are at least three left-handers?

Guest Mar 21, 2015

Best Answer 

 #1
avatar+81029 
+10

This is equal to... 1 - P(less than 3 left-handed people)  ....so....

P(no left-handed people]  = C(40, 0)(.90)^40 = .0148

P(1 left-handed person) = C(40, 1) (.90)^39 (.10)^1 = .066

P(2 left-handed people)  = C(40, 2) (.90)^38 (.10)^2 = .142

 

So

P(at least 3 left-handed people)  = 1 - P(less than 3 left-handed people) =

1 - .0148 - .066 - .142  =  about 77.7%

 

  

CPhill  Mar 22, 2015
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3+0 Answers

 #1
avatar+81029 
+10
Best Answer

This is equal to... 1 - P(less than 3 left-handed people)  ....so....

P(no left-handed people]  = C(40, 0)(.90)^40 = .0148

P(1 left-handed person) = C(40, 1) (.90)^39 (.10)^1 = .066

P(2 left-handed people)  = C(40, 2) (.90)^38 (.10)^2 = .142

 

So

P(at least 3 left-handed people)  = 1 - P(less than 3 left-handed people) =

1 - .0148 - .066 - .142  =  about 77.7%

 

  

CPhill  Mar 22, 2015
 #2
avatar+91467 
+5

Yes that is how I would have done it too. :)

Melody  Mar 22, 2015
 #3
avatar+81029 
0

Thanks, Melody.....!!!!

 

  

CPhill  Mar 22, 2015

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