3 lg x= lg10
Assuming that 'lg' means 'log' (either base 10 or base 2):
3 lg( x ) = lg( x3 )
So, the equation becomes 3 lg( x ) = lg( 10 ) ---> lg( x3 ) = lg( 10 ) ---> x3 = 10
---> x = cuberoot( 10 )
