+83 If
\(f(x) = \frac{2x-8}{x^2 -2x - 3} \qquad\text{ and }\qquad g(x) = \frac{3x+9}{2x-4}\)
What is the horizontal asymptote as \(x \) approaches negative infinity of \(f(g(x))\)?
+118608
\(f(x) = \frac{2x-8}{x^2 -2x - 3} \qquad\text{ and }\qquad g(x) = \frac{3x+9}{2x-4}\)
I found \(f( \frac{3x+9}{2x-4}) \) and then I simplified it all down.
There was a lot of algebra and I have not checked my result. Checking could be done by graphing the original substituted function
anyway I ended up with [ -40(x^2+....)] / [-15(x^2+....) ] if this is correct I would assume that the horizontal asymptote is
40/15 = 8/3
But there could be 100 mistakes in my working and also in my logic.
