If f(x) = (x + 4)/(x^2 + ax + b) and f(x) has two vertical asymptotes at x=1 and x=2, then find the sum of a and b.
+1223 Because the asymptotes are at x = 1 and x = 2, the factors in the denominator is (x-1)(x-2) = x^2 - 3x + 2.
So, a = -3 and b = 2, which has a sum of -1.
