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At a booth at the school carnival in past years, they've found that 28% of students win a stuffed toy ($3.65), 14% of students win a jump rope ($1.20), and 8% of students win a t-shirt ($7.50). The remaining students do not win a prize. If 250 students play the game at the booth, how much money should the carnival committee expect to pay for prizes for that booth?

 Jun 17, 2015

Best Answer 

 #2
avatar+30354 
+10

28% = 28/100 = 0.28;  14% = 14/100 = 0.14;  8% = 8/100 = 0.08 so:

 

money = 0.28*250*3.65 + 0.14*250*1.2 + 0.08*250*7.5

 

$${\mathtt{money}} = \left({\mathtt{0.28}}{\mathtt{\,\times\,}}{\mathtt{3.65}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.14}}{\mathtt{\,\times\,}}{\mathtt{1.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.08}}{\mathtt{\,\times\,}}{\mathtt{7.5}}\right){\mathtt{\,\times\,}}{\mathtt{250}} \Rightarrow {\mathtt{money}} = {\mathtt{447.5}}$$

 

money = $447.50

 

.

 Jun 18, 2015
 #1
avatar
+5

447.50

 Jun 18, 2015
 #2
avatar+30354 
+10
Best Answer

28% = 28/100 = 0.28;  14% = 14/100 = 0.14;  8% = 8/100 = 0.08 so:

 

money = 0.28*250*3.65 + 0.14*250*1.2 + 0.08*250*7.5

 

$${\mathtt{money}} = \left({\mathtt{0.28}}{\mathtt{\,\times\,}}{\mathtt{3.65}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.14}}{\mathtt{\,\times\,}}{\mathtt{1.2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.08}}{\mathtt{\,\times\,}}{\mathtt{7.5}}\right){\mathtt{\,\times\,}}{\mathtt{250}} \Rightarrow {\mathtt{money}} = {\mathtt{447.5}}$$

 

money = $447.50

 

.

Alan Jun 18, 2015

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