Athena heade for the rodeo at 9am @ 30mph. At 11am, Brad headed after her @ 60mph. What time was it when Brad caught Athena?

Guest Aug 19, 2015

#1**+5 **

Let t represent the number of hours that Brad drove.

Since Athena started 2 hours earlier, she drove t + 2 hours.

Distance = rate x time

Brad's distance: 60t

Athena's distance: 30(t + 2)

Assuming that they started in the same place, when Brad catches Athena, they both will have driven the same distance:

60t = 30(t + 2)

60t = 30t + 60

30t = 60

t = 2 hours (after Brad started, so 1:00 pm)

geno3141 Aug 19, 2015

#1**+5 **

Best Answer

Let t represent the number of hours that Brad drove.

Since Athena started 2 hours earlier, she drove t + 2 hours.

Distance = rate x time

Brad's distance: 60t

Athena's distance: 30(t + 2)

Assuming that they started in the same place, when Brad catches Athena, they both will have driven the same distance:

60t = 30(t + 2)

60t = 30t + 60

30t = 60

t = 2 hours (after Brad started, so 1:00 pm)

geno3141 Aug 19, 2015