+0  
 
0
303
1
avatar

Athena heade for the rodeo at 9am @ 30mph. At 11am, Brad headed after her @ 60mph. What time was it when Brad caught Athena?

 Aug 19, 2015

Best Answer 

 #1
avatar+17747 
+5

Let  t  represent the number of hours that Brad drove.

Since Athena started 2 hours earlier, she drove  t + 2 hours.

Distance  =  rate x time

Brad's distance:  60t

Athena's distance:  30(t + 2)

Assuming that they started in the same place, when Brad catches Athena, they both will have driven the same distance:

     60t  =  30(t + 2)

     60t  =  30t + 60

     30t  =  60

         t  =  2 hours (after Brad started, so 1:00 pm)

 Aug 19, 2015
 #1
avatar+17747 
+5
Best Answer

Let  t  represent the number of hours that Brad drove.

Since Athena started 2 hours earlier, she drove  t + 2 hours.

Distance  =  rate x time

Brad's distance:  60t

Athena's distance:  30(t + 2)

Assuming that they started in the same place, when Brad catches Athena, they both will have driven the same distance:

     60t  =  30(t + 2)

     60t  =  30t + 60

     30t  =  60

         t  =  2 hours (after Brad started, so 1:00 pm)

geno3141 Aug 19, 2015

26 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.