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Attempt to derive the formula for the sum of two cubes. (Proof)

 Sep 16, 2017
 #1
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Note

 

(a + b)^3   =  a^3  + 3a^2b + 3ab^2 + b^3

 

(a + b) ^3  = a^3 + 3ab (a + b) + b^3 

 

(a + b) ^3   -   3ab (a + b)  =  a^3  + b^3

 

(a + b)  [( a + b)^2 - 3ab ]  = a^3 + b^3

 

(a + b) ( a^2 + 2ab + b^2 - 3ab)  = a^3 + b^3

 

(a + b) ( a^2 - ab + b^2 )  = a^3 + b^3

 

 

cool cool cool

 Sep 16, 2017

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