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avatar+118677 
Hi Stu,
I would like to know how much you have learned.
I would like you to answer these questions if you can.
I hope that you don't mind me asking you these questions but it will give us a better idea of how you are going.
(If you don't want to answer them publicly, maybe you would like to message the answers to me but it would be a good indicator for other people who are trying to help you as well.)
Please just copy this onto the new post and write your answers under the questions so that they are easy for us to find and read.

1. Differentiate (use appropiate symbols)
a) y = x 9
b) f(x)=5x 3 - 3x + 6
c) y = 4x -5

2. d/dx (-12x)

3. differentiate
a) y = (2x+3) 4
a) f(x) = x 2 ( 2x+3) 4

Thanks,
Melody.
 Apr 6, 2014
 #1
avatar+1313 
0
1. Differentiate (use appropiate symbols)
a) y = x 9
y'=9x 8

b) f(x)=5x 3 - 3x + 6
f'(x)=15x 2 -3

c) y = 4x -5
y'=20x 4

2. d/dx (-12x)
f"(x) = -12

3. differentiate
a) y = (2x+3) 4
y' = 4*(2x+3 3*2

a) f(x) = x 2 ( 2x+3) 4
f'= 2x+4*(2x+3) 3*2

Thanks,
Melody.[/quote]
 Apr 8, 2014
 #2
avatar+1313 
0
Thanks feed back to me. I did have to check on the formulas.
 Apr 8, 2014
 #3
avatar+118677 
0
thanks Stu,

Stu:

1. Differentiate (use appropiate notation)
a) y = x9
y'=9x8

b) f(x)=5x3 - 3x + 6
f'(x)=15x2 -3

c) y = 4x-5
y'=20x4 (You could have used dy/dx= but y' is fine as well - But it should have been y' = -20x-5-1 = ?) Can you finish this please Stu

2. d/dx (-12x)
f"(x) = -12 Not f"(x) You only use " when you differentiate twice.
The best answer would be d/dx (-12x) = -12

3. differentiate
a) y = (2x+3)4
y' = 4*(2x+3)3*2 That is correct but you can simplify this answer.

b) f(x) = x2 ( 2x+3)4
f'= 2x+4*(2x+3)3*2

b) f(x) = x2 ( 2x+3)4
For this question you need to use the product rule. If y=uv then y'=uv' + vu'
u=x2 so u'=2x
v=(2x+3)4 so v'=4(2x+3)3*2 = 8(2x+3)3
Now you have to substitute those values into the formula and simplify the answer.
Could you try doing that please Stu?

Thanks,
Melody.

[/quote]
 Apr 8, 2014

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