A passenger plane flew from NY city to Los Angeles non-stop in 5 equal distances at the following average speeds for each distance: 600 km/h, 750 km/h, 800 km/h, 650 km/h and 825 km/h. What was the average speed of the plane from NY to LA? Thank you.
Let each "equal distance" as L.
The time taken for each "equal distance" is calculated by time = (distance)/(speed) = \(\dfrac L{600}, \dfrac L{750}, \cdots, \dfrac L{825}\).
Average speed = (distance)/(time) = \(\dfrac{5L}{\dfrac L{600} + \dfrac L{750} + \dfrac L{800} + \dfrac L{650} + \dfrac L{825}} = \dfrac 5{\dfrac1{600} + \dfrac 1{750} + \dfrac1{800} + \dfrac1{650} + \dfrac1{825}}\).
Now you can use a calculator to get the required average speed.