Average Velocity

I'm confused, Yura_chan.....if   s(t)  =  sqrt(4t)   is the position function.....then....the average velocity  =  

[change in position]  / time traveled 

The  position  at t = 4 = sqrt(4*4)  = 4 cm

And the position at t = 1 = sqrt(4*1)  =  2cm

So ......

It moves 2cm  in 3 seconds    =  2/3  cm  per second....

Avg velocity  = [ s(b)  - s(a)] / [ b  - a  ]      where b = 4 and a = 1    .....so we have...

[ sqrt(4*4)  -  sqrt(4*1)]  /  [ 4 - 1  ]  =

[ sqrt(16)  -  sqrt(4)]  /  [ 4 - 1  ]  =

[4  -  2 ] / 3  =

2  / 3    

I thought I'd have to use the formula f(x)-f(c)/x-c 
Is what I've been doing correct?

I think that's a bit different from what you mentioned.  It's question 1.

Sorry, you're correct. I just noticed the format they used in my textbook is the same that you mentioned.


Thank you!! :)

I wrote a big complement for you in here before Yura_chan and now it has disapeared.  There is not even a draft here for me to reaload 

Anyway.....

I said thank you to Chris for answering your question.  

and

I said I was very pleased that you quized him when you didn't understand.

We want everyone to do that, it proves we really do have a student who is learning from us :)

You answer other people's questions great too.

We are very lucky that you have joined our web2.0calc forum   

Thank you :) 

I love this site so much! Calc is really a k****r for me and there is no way I can pass the class without understanding the subject matter. All of you guys are super smart and helpful!! So thank you to Chris and you, and everyone else :)