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The entries in a certain row of Pascal's triangle are
\[1, n, \dots, n, 1.\]
The average of the entries in this row is $4/3$.  Find $n$.

 Dec 23, 2023
 #1
avatar+129849 
+1

The sum of any  row of entries =  2^n , where n = 0,1,2,3........

 

So the average =   2^n / ( n + 1)     where n = 0,1,2,3.....

 

So

 

2^n / ( n + 1)  =  4/3

 

Note that this is true when  n =  2

 

 

cool cool cool

 Dec 24, 2023

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