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# base number arithmetic

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12
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+4

Suppose that \$A\$, \$B\$, and \$C\$ are non-zero distinct digits less than \$6\$, and suppose we have \${AB_6}+{C_6}={C}0_6\$ and \${AB_6}+{BA_6}={CC_6}\$. Find the three-digit number \${ABC}\$. (Interpret \$AB_6\$ as a base-6 number with digits \$A\$ and \$B\$, not as \$A\$ times \$B\$. The other expressions should be interpreted in this way as well).

Dec 23, 2023

#1
+1690
0

Converting the first equation to base 10, we have 6A+B+C=6C. Simplifying, we have 6A+B=5C.

Converting the second equation to base 10, we have 6A+B+6B+A=6C+C. Simplifying, we have 7A+7B=7C. Dividing both sides by 7, we have A+B=C.

Substituting C=A+B into the first equation, we have 6A+B+A+B=6(A+B). Simplifying, we have 8A+2B=6A+6B. Combining like terms, we have 2A=4B. Dividing both sides by 2, we have A=2B.

Since A, B, and C are distinct digits less than 6, the only possible values for (A,B,C) are (2,1,3) and (4,2,6). However, C must be less than 6, so the only solution is ABC = 213.

Dec 24, 2023