+0  
 
0
52
1
avatar

In this problem, a and b are positive integers. When a is written in base 9, its last digit is 5. When b is written in base 6, its last two digits are 15. When a-b is written in base 3, what are its last two digits? Assume a-b is positive.

 Dec 8, 2020
 #1
avatar+114221 
+1

Base  6  number =  m(6^2)  + 1(6)  + 5  =   36m + 11

Let  m  = 1...  =  1156  =    4710  

 

Base  9 number

n(9)  + 5 

Let n = 5  .... =  559  =     5010

 

5010 - 4710  =   310   =   103

 

The last two digits are  1 and 0

 

cool cool cool

 Dec 8, 2020

25 Online Users