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This question is based on Similar Triangles

 

 Oct 15, 2018
 #1
avatar+98197 
+2

ABC  is a right triangle  with  AC the hypotenuse  = 5

Its area  = (1/2) product of the leg lenghts =   (1/2) (3 * 4)   = 6

Since its base is  5.....its altitude is

 

6  = (1/2) AC * altitude

 

12  = 5 * altitude

 

altitude  = 12/5

 

And triangle WBZ is similar to triangle ABC

 

So

 

altitude of WBZ  / base of WBZ  = altitude of ABC  / base of ABC

 

 

(12/5  - S ] / S  = (12/5) / 5      where S  = the side of the square

 

(12/5 - S) * 5 = (12/5)S

 

12 - 5S  = (12/5)S

 

12 =  5S + (12/5)S

 

12 = S [ 5 + 12/5 ]

 

12 = S [  37/5 ] 

 

!2 [ 5/37]  = S

 

60/37    =  S

 

 

cool cool cool

 Oct 15, 2018
 #2
avatar+464 
+1

Thank you Chris

 Oct 16, 2018

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