HI. This question is confusing me. We need to fine the measurements for m.
a) The area of the triangle is \(33 \times 56 \div 2 = 924\)
The hypotenuse of the triangle is \(\sqrt{33^3 + 56^2} = 65\).
So, the length of m is \(924 \div 56 \times 2 = {\color{brown}\boxed{1848 \over 65}} \approx 28.4307\)
b) Set up a ratio table: \({19 \over m} = {22 \over 14}\)
Now, just solve for m.
c) I'm not very confident about this one, but the 2 triangles are similar (reflect the smaller triangles so the angles match up.)
Then, the left side has a side length of 32, so we have another ratio table: \({32 \over 16} = {17 \over m}\)