+385 A number is chosen at random from the set of consecutive natural numbers $\{1, 2, 3, \ldots, 24\}$. What is the probability that the number chosen is a factor of $4!$? Express your answer as a common fraction.
+34 \(\)4!=24
The factors of 24 are 1,2,3,4,6,8,12,24 and there are 8 of them
Therefore there is an \(\frac{8}{24}\) or \(\frac{1}{3}\) chance that the number chosen is a factor of 4!
Hope this helps!
-Ako
+934 In 4 factorial , it is 1*2*3*4 which factorizes to 2^3*3. This means is has 8 factors: 1,2,3,4,6,8,12, and 24. If a number is randomly chosen from 1-24, 8 out of the 24 would be factors of 4!. That means your answer will be 8/24=1/3.
Hope it helps!
