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A jet flies 460 miles at a bearing of N 40° E. It then flies 270 miles with a bearing of S 10° E. How far is the plane from its starting point, and at what bearing? Round answers to the nearest tenth of a mile and nearest tenth of a degree.

 Feb 15, 2021

Best Answer 

 #1
avatar+29193 
+2

If I understand the notation correctly 460 miles 40o N of east       then    270 miles 10o S of east

 

Find the   components and add them together

 

460 sin 40 - 270 sin 10    =    248.797  miles North

460 cos 40 + 270 cos 10 =    618.278  miles East

 

Distance from origin   = sqrt ( 248.7972  + 618.2782 ) = 666.46 miles

       angle = arctan ( 248.797/618.278) = 21.92 degrees N of east

 Feb 15, 2021
 #1
avatar+29193 
+2
Best Answer

If I understand the notation correctly 460 miles 40o N of east       then    270 miles 10o S of east

 

Find the   components and add them together

 

460 sin 40 - 270 sin 10    =    248.797  miles North

460 cos 40 + 270 cos 10 =    618.278  miles East

 

Distance from origin   = sqrt ( 248.7972  + 618.2782 ) = 666.46 miles

       angle = arctan ( 248.797/618.278) = 21.92 degrees N of east

ElectricPavlov Feb 15, 2021

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