A jet flies 460 miles at a bearing of N 40° E. It then flies 270 miles with a bearing of S 10° E. How far is the plane from its starting point, and at what bearing? Round answers to the nearest tenth of a mile and nearest tenth of a degree.
+37157 If I understand the notation correctly 460 miles 40o N of east then 270 miles 10o S of east
Find the components and add them together
460 sin 40 - 270 sin 10 = 248.797 miles North
460 cos 40 + 270 cos 10 = 618.278 miles East
Distance from origin = sqrt ( 248.7972 + 618.2782 ) = 666.46 miles
angle = arctan ( 248.797/618.278) = 21.92 degrees N of east
+37157 If I understand the notation correctly 460 miles 40o N of east then 270 miles 10o S of east
Find the components and add them together
460 sin 40 - 270 sin 10 = 248.797 miles North
460 cos 40 + 270 cos 10 = 618.278 miles East
Distance from origin = sqrt ( 248.7972 + 618.2782 ) = 666.46 miles
angle = arctan ( 248.797/618.278) = 21.92 degrees N of east
