aircraft dlies due south 100km and due west 250km, find distance and bearing from start point
\(a^2+b^2=c^2\)
\(100^2+250^2=c^2\)
\(\sqrt{100^2+250^2}= 269.2582403567252016\)
Answer:269.3
is the bearing 90 degrees?
yes
The distance Solveit gave is correct.....however, the bearing is given by :
arctan[250/100] = 68.2° = S68.2°W [sometimes also expressed as (180 + 68.2)° = 248°]
