binompdf (6,.4,2)
binompdf (6,.4,2) ?
binompdf (6,.4,2) ? binompdf (n, p, x)=(nx)⋅px⋅qn−x
p=0.4q=(1−p)=1−0.4=0.6n=6x=2binompdf (6,.4,2)=P(X=2)=(62)⋅0.42⋅0.64=62⋅51⋅0.42⋅0.64=15⋅0.42⋅0.64=15⋅0.16⋅0.64=15⋅0.16⋅0.1296=0.31104=31.104 %
0.31104