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The triangle $\triangle ABC$ is an isosceles triangle where $AB = 4\sqrt{2}$ and $\angle B$ is a right angle. If $I$ is the incenter of $\triangle ABC,$ then what is $BI$?

Express your answer in the form $a + b\sqrt{c},$ where $a,$ $b,$ and $c$ are integers, and $c$ is not divisible by any perfect square other than $1.$

 Mar 3, 2021
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https://web2.0calc.com/questions/i-need-some-help-thank-you

Same question

 

Search up your question online before asking for help on here, it probably has already been solved before

 Mar 3, 2021

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