Let AB be a diameter of a circle, and let C be a point on the circle such that AC=8 and BC=4 The angle bisector of ACB intersects the circle at point M Find CM.

Guest Nov 17, 2022

#1**0 **

The angle bisector of ACB intersects the circle at point M Find CM.

**Hello Guest!**

Point C is on the periphery of the Thales circle of diameter AB.

Triangle ABC is a right triangle. The following applies:

\(\overline{AB}=\sqrt{\overline{AC}\ ^2+\overline{BC}\ ^2}=\sqrt{8^2+4^2}=\sqrt{64+16}=8.944\)

To be continued today.

!

asinus Nov 17, 2022