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In how many ways can $4$ balls be placed in $8$ boxes if neither the balls nor the boxes are distinguishable?

 Jan 20, 2024
 #1
avatar+129820 
+1

Since all the boces are the same, this  boils down to partitions of  4

 

4            in any  one box

2 2         in any  two boxes

1 3         in any two boxes

1 2 1      in any three boxes

1 1 1 1   in any  four  boxes

 

5 ways

 

cool cool cool

 Jan 20, 2024

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