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Brent rolls a fair dodecahedral die with numbers $1,2,3,...,12$ on its faces. What is the expected number of digits in the number he obtains? Express your answer in a decimal.

 Apr 27, 2015

Best Answer 

 #1
avatar+23252 
+10

9 sides have 1 digit (1, 2, 3, ..., 9) and 3 sides have 2 digits (10, 11, 12)

Total number of digits:  1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 2 + 2 + 2  =  15

Divide this value by the number of sides:

15 /12  =  1.25

 Apr 27, 2015
 #1
avatar+23252 
+10
Best Answer

9 sides have 1 digit (1, 2, 3, ..., 9) and 3 sides have 2 digits (10, 11, 12)

Total number of digits:  1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 2 + 2 + 2  =  15

Divide this value by the number of sides:

15 /12  =  1.25

geno3141 Apr 27, 2015
 #2
avatar+1836 
0

Thank you so much geno!!!

 Apr 27, 2015
 #3
avatar+129852 
0

Nice, geno.....!!!!

 

 

  

 Apr 28, 2015

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