Suppose the ratio of Lev's age to Mina's age is 1 : 2 and the ratio of Mina's age to Naomi's age is 3 : 4. If the sum of all three ages is between 30 and 50, then how old is Mina?

ColtPatterson Jan 13, 2019

#1**+1 **

Let Naomi's age = x

Then Mina's age is (3/4)x

And Lev's age = (3/8)x

So the sum of the ages = x + (3/4)x + (3/8) x = (17/8)x

Then Naomi's age must be divisible by 8

And it must be greater than 8 because 8 +(3/4)(8) + (3/8)(8) = 8 + 6 + 3 = only 17

So.....

Let Naomi's age = 16

Then Mna's age = (3/4)(16) = 12

And Lev's age = (3/8)(16) = 6

So 16 + 12 + 6 = 34

So....Mina is 12

CPhill Jan 13, 2019

#2**+2 **

As we found in one of your previous postings L:M:N is 3:6:8

3+6+8 =17 Not between 30 and 50 so let's double them all (this will keep the same ratios

L:M:N 6:12:16 6+12+16 = 34 satisfies the requirements

L=6

M=12

N=16

ElectricPavlov Jan 13, 2019