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Suppose the ratio of Lev's age to Mina's age is 1 : 2 and the ratio of Mina's age to Naomi's age is 3 : 4. If the sum of all three ages is between 30 and 50, then how old is Mina?

 Jan 13, 2019
 #1
avatar+100546 
+1

Let Naomi's age =  x

Then Mina's age is (3/4)x

And Lev's age = (3/8)x

 

So  the sum of the ages =     x + (3/4)x + (3/8) x  = (17/8)x

 

Then Naomi's age  must be divisible by 8

And it must be greater than 8 because 8 +(3/4)(8) + (3/8)(8)  =  8 + 6 + 3  =  only 17

So.....

Let Naomi's age =  16

Then Mna's age =  (3/4)(16) = 12

And Lev's age = (3/8)(16) = 6

 

So   16 + 12 + 6  =  34

 

So....Mina is 12

 

 

cool cool cool

 Jan 13, 2019
 #2
avatar+18346 
+2

As we found in one of your previous postings    L:M:N   is 3:6:8  

3+6+8 =17     Not between 30 and 50    so let's double them all (this will keep the same ratios

L:M:N  6:12:16      6+12+16 = 34    satisfies the requirements

L=6

M=12

N=16

 Jan 13, 2019

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