+0  
 
0
104
4
avatar+946 

 

 

Little bit of help please? 

Julius  Mar 16, 2018
 #1
avatar+87600 
+2

Subbing x for t......look at the graph here, Julius

 

https://www.desmos.com/calculator/6wqntzjcax

 

The graph has a positive slope  from  [0, 3]....so the max is reached at 3 months  ≈  512.733 (thousands)

 

cool cool cool 

CPhill  Mar 16, 2018
 #2
avatar+946 
0

I see that. But how do you do it algebraically? 

Julius  Mar 16, 2018
 #3
avatar
0

Wouldn't you just sub 3 for for t in your given function? Try it:

P(3) =4*3 + (100*3 / 3^2+400) + 500

P(3) = 12 +  (300 / 409) + 500

P(3) = 12 +  0.733496...  + 500

P(3) = 512.733486......

Guest Mar 16, 2018
 #4
avatar+946 
0

True: But w/o seeing the graph how would you know that at 3 months it's at its maximum population?

Julius  Mar 16, 2018

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