Calc

$h(x)\,=\,5f(x)-\frac23g(x)\\~\\ \frac{d}{dx}[h(x)]\,=\,\frac{d}{dx}[5f(x)-\frac23g(x)]\\~\\ \frac{d}{dx}[h(x)]\,=\,\frac{d}{dx}[5f(x)]-\frac{d}{dx}[\frac23g(x)]\\~\\ \frac{d}{dx}[h(x)]\,=\,5\frac{d}{dx}[f(x)]-\frac23\frac{d}{dx}[g(x)]\\~\\ h'(x)\,=\,5f'(x)-\frac23g'(x)$

That is the most you can say I think. 

Landry, are you sure this question is written properly?   

I eventually got the answer. 

h(x)=5f(x)−23g(x)

d/dx[h(x)]=d/dx[5f(x)−23g(x)]

h ′(x)=d/dx[5f(x)]−d/dx[23g(x)]

h ′(x)=5d/dx[f(x)]−23d/dx[g(x)]

h ′(x)=5f ′(x)−23g ′(x)

h ′(4)=5f ′(4)−23g ′(4)

h ′(4)=5∗3−23∗4

h ′(4)=15−83

h ′(4)=453−83

h ′(4)=45−83

h ′(4)=373