Calculate the Keq value for the synthesis of liquid water according to the following reaction, given equilbirum concentrations.
2H2(g) + O2(g) <----> 2H2O(l) + energy
[H2O] = 1.57 x 10^-4 M
[H2] = 2.038 M
[O2] = 1.554 M
An answer in scientifi notation such as 8.51 x 10-4 can be formatted as follows; 8.51E-4 or 8.51X10^-4 or .000851
I cannot figure out this thing for my life. Please help
