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Find the slope of the line tangent to the graph of f at P.

 

\(f(x) = x^2 - 5; P(3,4)\)

 

The answer is 6, but I have no idea how to get it there

CurlyFry  Mar 1, 2018

Best Answer 

 #1
avatar+13514 
+3

The derivative of

x^2 -5 =

 

2 x^(2-1) = 2x      Now substitute the value you have for x at your point  (3,4)

2(3) = 6

ElectricPavlov  Mar 1, 2018
 #1
avatar+13514 
+3
Best Answer

The derivative of

x^2 -5 =

 

2 x^(2-1) = 2x      Now substitute the value you have for x at your point  (3,4)

2(3) = 6

ElectricPavlov  Mar 1, 2018

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