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Find the slope of the line tangent to the graph of f at P.
\(f(x) = x^2 - 5; P(3,4)\)
The answer is 6, but I have no idea how to get it there
The derivative of
x^2 -5 =
2 x^(2-1) = 2x Now substitute the value you have for x at your point (3,4)
2(3) = 6