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Locate the discontinuities of the function y = ln(tan2x)
 Oct 16, 2013
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tan(2x) is undefined or discontiunuous for x=(pi/4)+-(pi/2)k where k is any integer

y = lnx has the domain x>0

so now considering
y=ln(tan(2x))

tan(2x)>0
true for
0 < x <pi/4
2pi/4 < x < 3pi/4
4pi/4 < x < 5pi/4

etc, this is where it is defined, NOT where it is NOT defined.

so It is not defined for

-pi/4 <= x <= 0
pi/4 <= x <= 2pi/4
3pi/4 <= x <= pi etc

I think this is

(pi/4) +- (pi/2*k) <= x <= (pi/2) +- (pi/2*k) Where k is an integer
I think that this is where the function is undefined.

I also plotted it using http://rechneronline.de/function-graphs/

I think that the graph supports my conclusion but I will admit that I havn't looked at it that hard.

y=ln(tan2x).JPG
 Oct 16, 2013

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