+0

# calculus help

0
133
10

https://prnt.sc/pfqre3

thank you very much any help is appreciated

Oct 7, 2019
edited by Melody  Oct 7, 2019

#1
+2417
0

Sorry blocked on my browser

Oct 7, 2019
#2
+2417
+2

Thanks melody!

CalculatorUser  Oct 7, 2019
#3
+2417
+3

This is basically what the question is asking

Lets say the sun is located at the focus of the left side of the image

____________________________________________________

So the distance between the perihelion and aphelion should be 46 + 70 = 116 million miles??

I haven't learned much in calculus yet this is as much as I can give you

Oct 7, 2019
#4
+2417
+2

2)

We can try to find the distance of the perihelion to the center of the ellipse.

116 / 2 = 58 million miles

58 - 46 (distance from perhelion to sun) = 12 million miles between sun and center of ellipse

CalculatorUser  Oct 7, 2019
#5
+1

thank you both so much!!

Oct 7, 2019
#6
+2417
0

Welcome!

CalculatorUser  Oct 7, 2019
#7
0

im sorry to trouble you i have one more question.

im not sure how to set this up

"Write the equation of the elliptical orbit of Mercury, where the major axis runs horizontally. Allow a and b to be measured in millions of miles. Use the origin as the center of the ellipse."

Oct 7, 2019
#8
+2417
+1

Do you know how to write ellipse equations?

Standard form $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$

With $$a>b$$.

The value of A I think is just the distance of the origin to the endpoint of the horizontal axis

The value of B is the distance from the origin to the endpoint of the vertical axis.

CalculatorUser  Oct 8, 2019
#9
0

what is my origin/center?

Oct 9, 2019
#10
0

nvm its (0,0)

Guest Oct 9, 2019