What is the integral of ^^?

Let s+1 = u

Then s = u -1

And ds = 1 du

So we have

4pi∫(u - 1)/u³ du =

4pi [∫1/u^-2 du - ∫ u^-3 du ] + C =

4pi [ (-1)u^-1 - (-1/2)u^-2 ]  + C =

4pi [ 1/(2u²) - 1/u ] + C =

2pi [ 1- 2u]/ u² + C =   [back substitute ....( u = s+ 1) ]

2pi [ 1 -2(s + 1) ]/ (s + 1)² + C

2pi [ -(2s + 1) ] / (s + 1)² + C =

-2pi (2s + 1) / (s + 1)² + C