+0

# Calculus

+1
566
3

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motions

= 2 sin(π t) + 2 cos(π t),

where t is measured in seconds. (Round your answers to two decimal places.)

Find the average velocity during each time period.

(i)    [1, 2] (1 to 2 seconds)
____cm/s

(ii)    [1, 1.1]
____ cm/s

(iii)    [1, 1.01]
____cm/s

(iv)    [1, 1.001]
____cm/s

(b) Estimate the instantaneous velocity of the particle when t = 1.
____cm/s

Jan 29, 2019

#1
+1

2[  sin (pi *t  ) + cos (pi * t)

From 1 to 2 seconds we have

[  2 sin (2pi) + 2cos  (2 pi)  - 2sin (pi) - 2cos(pi)] / (2 - 1) =

[ 2  - (-2) ] / 1      =     4 cm /sec

From 1 to 1.1 seconds

[  2 sin (1.1pi) + 2cos  (1.1 pi)  - 2sin (pi) - 2cos(pi)] / (1.1 - 1) ≈  -5.20 cm/sec

From 1 to 1.01 seconds

[  2 sin (1.01*pi) + 2cos  (1.01* pi)  - 2sin (pi) - 2cos(pi)] / (1.01 - 1) ≈ -6.18 cm/sec

From  1 to 1.001 seconds

[  2 sin (1.001*pi) + 2cos  (1.001* pi)  - 2sin (pi) - 2cos(pi)] / (1.001 - 1)  ≈ - 6.27 cm /sec

It appears that  the instantaneous velocity at 1 sec   =  -2pi  cm/sec  ≈  -6.28 cm/sec

BTW....we can verify that this is true using some Calculus   !!!   Jan 29, 2019
#2
0

oh wow that's a lot. thank you

Ruublrr  Jan 29, 2019
#3
0

You're welcome.....!!!!   CPhill  Jan 29, 2019