+0  
 
+1
61
2
avatar+275 

(I just figured out I can use that "LaTeX" thing)

 

\(f(x)=2x^2-5x\)

Using ↑↑↑↑ that function up there

\( f(2x)-2f(x)\)

 Feb 6, 2019
 #1
avatar+79 
+2

So, you want me to find f(2x)-2f(x), huh?

 

In the above equation, you can just plug in 2x, which yields:

 

2(2x)^2-5(2x) = 8x^2 - 10x

 

Now we find 2f(x), which is just 2(2x^2-5x) = 4x^2 - 10x

 

subtracting 4x^2 - 10x from 8x^2 - 10x, we get 4x^2.

 Feb 6, 2019
 #2
avatar+99309 
0

Congratulations on figuring out some latex!!   laugh

 Feb 6, 2019

15 Online Users

avatar
avatar
avatar
avatar