+0  
 
+1
51
5
avatar+275 

Find the limit.

 

lim x→0   [sin(x^9)] / x

 Mar 3, 2019
 #1
avatar+17331 
+1

OK....it is a little bit annoying when you don't check your PREVIOUS posts....it is a bit MORE annoying when you do not post your Q's correctly in the FIRST place....but rather, you IGNORE your previous post and then RE-POST  !!!!!      We are NOT here to do your homework....please respond to your PREVIOUS MISTAKEN post rather than ignoring YOU made a MISTAKE....GRRRRRRRRrrrrr......

 Mar 3, 2019
 #2
avatar+275 
+1

I posted the wrong question and didn't want to edit it because last time I edited a question after I posted it someone got slightly upset. I figured just posting the actual question hours later would be better. 

Ruublrr  Mar 3, 2019
 #3
avatar+17331 
+1

Don't 'edit' your question after you post it and people (several) take their time to help you by responding!....Rather:  REPLY to your original post and explain that you made a mistake and the 'this' is what you meant........try that.....mucho better than ignoring everyone's efforts to help YOU !!!cheeky

 Mar 3, 2019
 #4
avatar+17331 
+1

See here:

 

https://www.symbolab.com/solver/limit-calculator/%5Clim_%7Bx%5Cto0%7D%5Cleft(%5Cfrac%7Bsin%5Cleft(x%5E%7B9%7D%5Cright)%7D%7Bx%7D%5Cright)

 Mar 3, 2019
 #5
avatar+275 
+2

Thank you.

Ruublrr  Mar 3, 2019

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