+0  
 
0
778
11
avatar+546 

Just want to thank anyone ahead of time for any help!

 

26) 4√64x^3y^6

28) 3√6* 3√16

30) √8x^5*√3x

32) 3 3√5y^3* 2 3√50y^4

(on number 32, the second 3 is part of the sqrt, the 1st 3 is in front of the equation.)

5) simplest form of?: 3√7x/3√5y^2

 Jul 18, 2014

Best Answer 

 #9
avatar+98141 
+5

32)   So, I assume we have  3*3√5y^3* 2*3√50y^4  ???

9√5y^3 * 6√50y^4

9√5y^3 * 6√(25*2)y^4

9√5y^3 * 6*5√(2)y^4

9√5y^3 * 30√(2)y^4

270(y^7)√10

 

 Jul 18, 2014
 #1
avatar+99324 
+5

26) 4√64x^3y^6

 

$$4\sqrt{64}x^3y^6\\\\
=4*8x^3y^6\\\\
=32x^3y^6\\\\$$

.
 Jul 18, 2014
 #2
avatar+99324 
+5

How about having a go at the next one Nataszaa and I will help if you get stuck.  

 Jul 18, 2014
 #3
avatar+546 
0

Thanks Melody! I am awful at this...i have spent weeks with my tutor on it but i will try.

 Jul 18, 2014
 #4
avatar+546 
0

for #28 i wasnt sure, but i went off of what you had posted.

so i get the sqrt of 6 and 16? which are 2&4...what next?

 Jul 18, 2014
 #5
avatar+98141 
+5

28) 3√6* 3√16

So we have

 3√6 * 3*4  =    note that we are just multiplying now, Nataszaa

3*3*4*√6 =

36√6    ...we can't do anything with the square root of 6 !!! 

--------------------------------------------------------------------------------------------------

30) √8x^5*√3x   =  √(2*2*2)x^5*√(3)x = √(4*2)x^5*√(3)x = 2√(2)x^5*√(3)x =

2* x^5 * x * √(2) * √(3)  =  (2x^6)√(6)

---------------------------------------------------------------------------------------------------

3√7x/3√5y^2 = (the 3's "cancel) = √7x/√5y^2= (Multiply the numerator and denominator by √5) =  (√35x)/(5y^2)

---------------------------------------------------------------------------------------------------

Nataszaa, repost 32 again.......are there some parenthesis involved???

 

 Jul 18, 2014
 #6
avatar+546 
0

inbetween the lines under number 30, is that a continuation?

 

Cphill

THANKS

 Jul 18, 2014
 #7
avatar+546 
0

32 was weird...posting wise...lol

 

its a normal 3 then a sqrt sign with another 3 in the opening start of the sign...i cant copy and paste :((

 Jul 18, 2014
 #8
avatar+98141 
+5

I did   5)  after 30....that's the one between the lines....I look at 32 in a sec !!!

 

 Jul 18, 2014
 #9
avatar+98141 
+5
Best Answer

32)   So, I assume we have  3*3√5y^3* 2*3√50y^4  ???

9√5y^3 * 6√50y^4

9√5y^3 * 6√(25*2)y^4

9√5y^3 * 6*5√(2)y^4

9√5y^3 * 30√(2)y^4

270(y^7)√10

 

CPhill Jul 18, 2014
 #10
avatar+546 
0

Sorry, CPhill

I messaged you about this equation. Turns ou that that the second three is cubed root.

so 3 cubedroot...

 Jul 18, 2014
 #11
avatar+7372 
0

32) \(3\sqrt[3]{5y^3}\times2\sqrt[3]{50y^4}\)

\(3y \sqrt[3]{5}\times 2\sqrt[3]{5\times5\times2\times y^3\times y}\)

\(6y\sqrt[3]{5}\times y \sqrt{50y}\)

\(6y^2 \sqrt[3]{250y}\)

\(6y^2 \sqrt[3]{5^3\times 2y}\)

\(6y^2\times 5 \sqrt[3]{2y}\)

\(30y^2\sqrt[3]{2y}\)

.
 Jul 2, 2016

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