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# Just want to thank anyone ahead of time for any help!

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Just want to thank anyone ahead of time for any help!

26) 4√64x^3y^6

28) 3√6* 3√16

30) √8x^5*√3x

32) 3 3√5y^3* 2 3√50y^4

(on number 32, the second 3 is part of the sqrt, the 1st 3 is in front of the equation.)

5) simplest form of?: 3√7x/3√5y^2

Jul 18, 2014

#9
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32)   So, I assume we have  3*3√5y^3* 2*3√50y^4  ???

9√5y^3 * 6√50y^4

9√5y^3 * 6√(25*2)y^4

9√5y^3 * 6*5√(2)y^4

9√5y^3 * 30√(2)y^4

270(y^7)√10

Jul 18, 2014

#1
+105683
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26) 4√64x^3y^6

$$4\sqrt{64}x^3y^6\\\\ =4*8x^3y^6\\\\ =32x^3y^6\\\\$$

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Jul 18, 2014
#2
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How about having a go at the next one Nataszaa and I will help if you get stuck.

Jul 18, 2014
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Thanks Melody! I am awful at this...i have spent weeks with my tutor on it but i will try.

Jul 18, 2014
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for #28 i wasnt sure, but i went off of what you had posted.

so i get the sqrt of 6 and 16? which are 2&4...what next?

Jul 18, 2014
#5
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28) 3√6* 3√16

So we have

3√6 * 3*4  =    note that we are just multiplying now, Nataszaa

3*3*4*√6 =

36√6    ...we can't do anything with the square root of 6 !!!

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30) √8x^5*√3x   =  √(2*2*2)x^5*√(3)x = √(4*2)x^5*√(3)x = 2√(2)x^5*√(3)x =

2* x^5 * x * √(2) * √(3)  =  (2x^6)√(6)

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3√7x/3√5y^2 = (the 3's "cancel) = √7x/√5y^2= (Multiply the numerator and denominator by √5) =  (√35x)/(5y^2)

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Nataszaa, repost 32 again.......are there some parenthesis involved???

Jul 18, 2014
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inbetween the lines under number 30, is that a continuation?

Cphill

THANKS

Jul 18, 2014
#7
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32 was weird...posting wise...lol

its a normal 3 then a sqrt sign with another 3 in the opening start of the sign...i cant copy and paste :((

Jul 18, 2014
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I did   5)  after 30....that's the one between the lines....I look at 32 in a sec !!!

Jul 18, 2014
#9
+104963
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32)   So, I assume we have  3*3√5y^3* 2*3√50y^4  ???

9√5y^3 * 6√50y^4

9√5y^3 * 6√(25*2)y^4

9√5y^3 * 6*5√(2)y^4

9√5y^3 * 30√(2)y^4

270(y^7)√10

CPhill Jul 18, 2014
#10
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Sorry, CPhill

so 3 cubedroot...

Jul 18, 2014
#11
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32) $$3\sqrt[3]{5y^3}\times2\sqrt[3]{50y^4}$$

$$3y \sqrt[3]{5}\times 2\sqrt[3]{5\times5\times2\times y^3\times y}$$

$$6y\sqrt[3]{5}\times y \sqrt{50y}$$

$$6y^2 \sqrt[3]{250y}$$

$$6y^2 \sqrt[3]{5^3\times 2y}$$

$$6y^2\times 5 \sqrt[3]{2y}$$

$$30y^2\sqrt[3]{2y}$$

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Jul 2, 2016