**Just want to thank anyone ahead of time for any help!**

26) *4*√64x^3y^6

28) *3*√6* *3*√16

30) √8x^5*√3x

32) 3 *3*√5y^3* 2 3√50y^4

(on number 32, the second 3 is part of the sqrt, the 1st 3 is in front of the equation.)

5) simplest form of?: 3√7x/3√5y^2

Nataszaa Jul 18, 2014

#2**+5 **

How about having a go at the next one Nataszaa and I will help if you get stuck.

Melody Jul 18, 2014

#3**0 **

Thanks Melody! I am awful at this...i have spent weeks with my tutor on it but i will try.

Nataszaa Jul 18, 2014

#4**0 **

for #28 i wasnt sure, but i went off of what you had posted.

so i get the sqrt of 6 and 16? which are 2&4...what next?

Nataszaa Jul 18, 2014

#5**+5 **

28) *3*√6* *3*√16

So we have

*3*√6 * *3**4 = note that we are just multiplying now, Nataszaa

3*3*4*√6 =

36√6 ...we can't do anything with the square root of 6 !!!

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30) √8x^5*√3x = √(2*2*2)x^5*√(3)x = √(4*2)x^5*√(3)x = 2√(2)x^5*√(3)x =

2* x^5 * x * √(2) * √(3) = (2x^6)√(6)

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3√7x/3√5y^2 = (the 3's "cancel) = √7x/√5y^2= (Multiply the numerator and denominator by √5) = (√35x)/(5y^2)

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Nataszaa, repost 32 again.......are there some parenthesis involved???

CPhill Jul 18, 2014

#7**0 **

32 was weird...posting wise...lol

its a normal 3 then a sqrt sign with another 3 in the opening start of the sign...i cant copy and paste :((

Nataszaa Jul 18, 2014

#8**+5 **

I did 5) after 30....that's the one between the lines....I look at 32 in a sec !!!

CPhill Jul 18, 2014

#9**+5 **

Best Answer

32) So, I assume we have 3**3*√5y^3* 2*3√50y^4 ???

9√5y^3 * 6√50y^4

9√5y^3 * 6√(25*2)y^4

9√5y^3 * 6*5√(2)y^4

9√5y^3 * 30√(2)y^4

270(y^7)√10

CPhill Jul 18, 2014

#10**0 **

Sorry, CPhill

I messaged you about this equation. Turns ou that that the second three is cubed root.

so 3 cubedroot...

Nataszaa Jul 18, 2014